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str rEplACE 1 2 3

select TRANSLATE('12341231323', '123','一二三') from dual;

str = str.replace("abc",",")str.split(',')就是你要的了

下面是一个replace字符串的例子:#include<stdio.h>#include<string.h>#define MAXLENGTH 100//调用的时候必须确保s1的长度足够容纳替换的字符串.void replace(char *s1, char *s2, char *s3) { int len1 = strlen(s1), len2=strlen(s2), len3 = strlen(

先用str_replace这个函数,再用explode是分割成为数组 $aaa="[1][2][3][4]"; $bbb=str_replace(']',',',str_replace('[','',$aaa)); $list=explode(",",$bbb); 自己把代码拿过去测试吧 希望能帮助到你.

String str = "1,2,3,4,5,6";(可以把从文件里的内容读存到str中)str = str.replaceAll(","," ");这样就可以了.

$str = '1,2,3,';$arr = explode(',',trim($str,','));

var reg = /(\d)([^\1]*)\1/g;var str = "1 2 1 3 3";str = str.replace(reg,"$1$2");console.log(str);

string name="123456";string name=name[0].tostring+","+name[1].tostring+","+name[2].tostring+","+name[3].tostring+","+name[4].tostring+","+name[5].tostring

同意sun_moon_stars 的写法,目前有两种做法1.直接进行替换,对逗号进行替换修改.2.使用split方法进行字符串的截取,得到String数组,然后遍历数组,添加''

<% str1 = "I like coffee "str2 = "coffee"str3 = "tea"x = replace(str1,str2,str3) response.write x' output -> I like tea %>

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