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用jAvA编程矩阵A 用数组

//Don't care about it!void main(){ int a[][]= {{1,2,3,4},{2,3,4,5},{3,4,5,6}}; int b[][]=new int[4][3]; for(int i=0;i

public class T { public static void main(String[] args) { int i,j; int[][] a = {{1,1,1},{2,2,2},{3,3,3}}; int[][] b = new int[3][3]; System.out.print("初始矩阵:\n"); for(i=0;i

public static void sort(char [] a){ //利用简单的冒泡排序 for(int x=0;x

public static void main(String[] args) { int a[][]={{1,2,3,4},{2,3,4,5},{3,4,5,6}}; int b[][]=new int[4][3]; for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i].length; j++) { b[j][i]=a[i][j]; } } for (int i = 0; i <...

还是可以使用冒泡、二分等 的排序方法 。。。。只是比较的不是数本身,而是对应的数组的元素。。。。。。。。。。。。

public static void main(String args[]){int temp;int r=0,c=0;int [][] iArr={{23,534,43},{32,32,30},{35,46,332},{412,1492,252}};temp=iArr[0][0];for(int i=0;i

import java.util.Scanner;public class Array {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);int [] a = new int[10];int count = 0;System.out.println("请输入10个整数");while (true) {if(scanner.ha...

public static void main(String[] args) throws Exception { int[] arr1 = new int[10]; int[] arr2 = new int[10]; Set set = new HashSet(); for (int anArr1 : arr1) { set.add(anArr1); //把第一个数组的值 全部放入set } for (int anArr2 ...

实现思路:就是分别取出来a数组中每一行每一列的值,之后与b数组中每一行每一列的值进行乘积计算 public class Test{ public static void main(String[]args){ int[][] a = new int[2][3]; int[][] b = new int[3][4]; int[][] c = new int[3][4...

import java.util.TreeMap;public class Test {// 统计数字或者字符出现的次数public static TreeMap Pross(String str) {char[] charArray = str.toCharArray();TreeMap tm = new TreeMap();for (int x = 0; x < charArray.length; x++) {if (!...

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